does boost::variant support 128 bit integer?

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David Frank

7 Apr 2021 7 Apr '21

6 p.m.

especially the gnu __int128?Thanks,David.

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Anil Muthigi

7 Apr 7 Apr

6:15 p.m.

I dont think so... I guess int128_t under boost/multiprecision/cpp_int is the only viable option. On Wed, 7 Apr 2021, 11:39 pm David Frank via Boost-users, < boost-users@lists.boost.org> wrote:

...

especially the gnu __int128? Thanks, David. _______________________________________________ Boost-users mailing list Boost-users@lists.boost.org https://lists.boost.org/mailman/listinfo.cgi/boost-users

Edward Diener

6:37 p.m.

On 4/7/2021 2:15 PM, Anil Muthigi via Boost-users wrote:

...

I dont think so...

If it is available why do you think variant would not support it ?

...

I guess int128_t under boost/multiprecision/cpp_int is the only viable option.

On Wed, 7 Apr 2021, 11:39 pm David Frank via Boost-users, mailto:boost-users@lists.boost.org> wrote:

especially the gnu __int128?

Anil Muthigi

7:38 p.m.

I said that I am not sure if boost::variant supports __int128 because I had difficulties in compiling this code : 1. #include 2. #include <string> 3. #include <iostream> 4. std::ostream& operator<<(std::ostream& o, const __int128& x) { if (x == std::numeric_limits<__int128>::min()) return o << "-170141183460469231731687303715884105728"; if (x < 0) return o << "-" << -x; if (x < 10) return o << (char)(x + '0'); return o << x / 10 << (char) (x % 10 + '0'); } 5. int main() 6. { 7. boost::variant<__int128, char, std::string> v; 8. v = 56; 9. v = 'Y'; 10. __int128 d=12; 11. std::cout < wrote:

...

On 4/7/2021 2:15 PM, Anil Muthigi via Boost-users wrote:

...
I dont think so...

If it is available why do you think variant would not support it ?

...
I guess int128_t under boost/multiprecision/cpp_int is the only viable option.

On Wed, 7 Apr 2021, 11:39 pm David Frank via Boost-users, mailto:boost-users@lists.boost.org> wrote:

especially the gnu __int128?

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Edward Diener

11 p.m.

On 4/7/2021 3:38 PM, Anil Muthigi via Boost-users wrote:

...

I said that I am not sure if boost::variant supports __int128 because I had difficulties in compiling this code :

1. #include 2. #include <string> 3. #include <iostream> 4. std::ostream& operator<<(std::ostream& o, const __int128& x) { if (x == std::numeric_limits<__int128>::min()) return o << "-170141183460469231731687303715884105728"; if (x < 0) return o << "-" << -x; if (x < 10) return o << (char)(x + '0'); return o << x / 10 << (char)(x % 10 + '0'); } 5. int main() 6. { 7. boost::variant<__int128, char, std::string> v; 8. v = 56; 9. v = 'Y'; 10. __int128 d=12; 11. std::cout <
If u replace __int128 with int in the variant variable, it seems to work just fine...

My test with gcc-10.2 and clang-linux-11.0 shows that it does not support __int128 in iostreams.

...

On Thu, 8 Apr 2021, 00:10 Edward Diener via Boost-users, mailto:boost-users@lists.boost.org> wrote:

On 4/7/2021 2:15 PM, Anil Muthigi via Boost-users wrote: > I dont think so...

If it is available why do you think variant would not support it ?

> I guess int128_t under boost/multiprecision/cpp_int is the only viable > option. > > On Wed, 7 Apr 2021, 11:39 pm David Frank via Boost-users, > mailto:boost-users@lists.boost.org mailto:boost-users@lists.boost.org>> wrote: > > especially the gnu __int128?

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Anil Muthigi

11:10 p.m.

If u see my code, I have used __int128 separately for the variable d as well. If u change the variant variable' s data type from __int128 to int , it will run just fine. On Thu, 8 Apr 2021, 04:30 Edward Diener via Boost-users, < boost-users@lists.boost.org> wrote:

...

On 4/7/2021 3:38 PM, Anil Muthigi via Boost-users wrote:

...
I said that I am not sure if boost::variant supports __int128 because I had difficulties in compiling this code :

1. #include 2. #include <string> 3. #include <iostream> 4. std::ostream& operator<<(std::ostream& o, const __int128& x) { if (x == std::numeric_limits<__int128>::min()) return o << "-170141183460469231731687303715884105728"; if (x < 0) return o << "-" << -x; if (x < 10) return o << (char)(x + '0'); return o << x / 10 << (char)(x % 10 + '0'); } 5. int main() 6. { 7. boost::variant<__int128, char, std::string> v; 8. v = 56; 9. v = 'Y'; 10. __int128 d=12; 11. std::cout <
If u replace __int128 with int in the variant variable, it seems to work just fine...

My test with gcc-10.2 and clang-linux-11.0 shows that it does not support __int128 in iostreams.

...
On Thu, 8 Apr 2021, 00:10 Edward Diener via Boost-users, mailto:boost-users@lists.boost.org>

wrote:

...
On 4/7/2021 2:15 PM, Anil Muthigi via Boost-users wrote: > I dont think so...

If it is available why do you think variant would not support it ?

> I guess int128_t under boost/multiprecision/cpp_int is the only viable > option. > > On Wed, 7 Apr 2021, 11:39 pm David Frank via Boost-users, > mailto:boost-users@lists.boost.org mailto:boost-users@lists.boost.org>> wrote: > > especially the gnu __int128?

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Edward Diener

8 Apr 8 Apr

1:58 a.m.

On 4/7/2021 7:10 PM, Anil Muthigi via Boost-users wrote:

...

If u see my code, I have used __int128 separately for the variable d as well. If u change the variant variable' s data type from __int128 to int , it will run just fine.

The reason your code is failing is because your stream operator uses streaming and __int128 has no stream support. If you use an __int128 in a variant, but never use streaming, your code is fine. I do not know the reason why gcc and clang support __int128 but do not support the the type in streaming. Maybe you should try asking gcc about it or investigate it as a stackoverflow question. Please do not topmost.

...

On Thu, 8 Apr 2021, 04:30 Edward Diener via Boost-users, mailto:boost-users@lists.boost.org> wrote:

On 4/7/2021 3:38 PM, Anil Muthigi via Boost-users wrote: > I said that I am not sure if boost::variant supports __int128 because I > had difficulties in compiling this code : > > 1. > #include > 2. > #include <string> > 3. > #include <iostream> > 4. > std::ostream& operator<<(std::ostream& o, const __int128& x) { if (x > == std::numeric_limits<__int128>::min()) return o << > "-170141183460469231731687303715884105728"; if (x < 0) return o << > "-" << -x; if (x < 10) return o << (char)(x + '0'); return o << x / > 10 << (char)(x % 10 + '0'); } > 5. > int main() > 6. > { > 7. > boost::variant<__int128, char, std::string> v; > 8. > v = 56; > 9. > v = 'Y'; > 10. > __int128 d=12; > 11. > std::cout < 12. > std::cout << v << '\n'; > 13. > v = "Yashaswi raj"; > 14. > std::cout << v << '\n'; > 15. > } > > If u replace __int128 with int in the variant variable, it seems to work > just fine...

My test with gcc-10.2 and clang-linux-11.0 shows that it does not support __int128 in iostreams.

Edward Diener

2:22 a.m.

On 4/7/2021 9:58 PM, Edward Diener via Boost-users wrote:

...

On 4/7/2021 7:10 PM, Anil Muthigi via Boost-users wrote:

...
If u see my code, I have used __int128 separately for the variable d as well. If u change the variant variable' s data type from __int128 to int , it will run just fine.

The reason your code is failing is because your stream operator uses streaming and __int128 has no stream support. If you use an __int128 in a variant, but never use streaming, your code is fine. I do not know the reason why gcc and clang support __int128 but do not support the the type in streaming. Maybe you should try asking gcc about it or investigate it as a stackoverflow question.

Please do not topmost.

Apologies ! It looks as if the variant i/o is simply not picking up your std::ostream& operator<<(std::ostream& o, const __int128& x) functionality. I tried putting your functionality in namespace boost but it still did not pick it up.

...

...
On Thu, 8 Apr 2021, 04:30 Edward Diener via Boost-users, mailto:boost-users@lists.boost.org> wrote:

On 4/7/2021 3:38 PM, Anil Muthigi via Boost-users wrote: > I said that I am not sure if boost::variant supports __int128 because I > had difficulties in compiling this code : > > 1. > #include > 2. > #include <string> > 3. > #include <iostream> > 4. > std::ostream& operator<<(std::ostream& o, const __int128& x) { if (x > == std::numeric_limits<__int128>::min()) return o << > "-170141183460469231731687303715884105728"; if (x < 0) return o << > "-" << -x; if (x < 10) return o << (char)(x + '0'); return o << x / > 10 << (char)(x % 10 + '0'); } > 5. > int main() > 6. > { > 7. > boost::variant<__int128, char, std::string> v; > 8. > v = 56; > 9. > v = 'Y'; > 10. > __int128 d=12; > 11. > std::cout < 12. > std::cout << v << '\n'; > 13. > v = "Yashaswi raj"; > 14. > std::cout << v << '\n'; > 15. > } > > If u replace __int128 with int in the variant variable, it seems to work > just fine...

My test with gcc-10.2 and clang-linux-11.0 shows that it does not support __int128 in iostreams.

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Anil Muthigi

2:33 a.m.

But I am not even doing any kind of input or output using __int128 FOR THE VARIANT VARIABLE…. As you can see… if you choose to use int instead of __int128 for the VARIANT VARIABLE and rerun the code…. it is actually printing the value of the __int128 variable d which I have used in the code.. So, I guess it is actually picking up my std::ostream& operator<<(std::ostream& o, const __int128& x) functionality.

...

On 08-Apr-2021, at 7:52 AM, Edward Diener via Boost-users wrote:

On 4/7/2021 9:58 PM, Edward Diener via Boost-users wrote:

...
On 4/7/2021 7:10 PM, Anil Muthigi via Boost-users wrote:

...
If u see my code, I have used __int128 separately for the variable d as well. If u change the variant variable' s data type from __int128 to int , it will run just fine. The reason your code is failing is because your stream operator uses streaming and __int128 has no stream support. If you use an __int128 in a variant, but never use streaming, your code is fine. I do not know the reason why gcc and clang support __int128 but do not support the the type in streaming. Maybe you should try asking gcc about it or investigate it as a stackoverflow question. Please do not topmost.

Apologies ! It looks as if the variant i/o is simply not picking up your std::ostream& operator<<(std::ostream& o, const __int128& x) functionality. I tried putting your functionality in namespace boost but it still did not pick it up.

...
...
On Thu, 8 Apr 2021, 04:30 Edward Diener via Boost-users, mailto:boost-users@lists.boost.org> wrote:

On 4/7/2021 3:38 PM, Anil Muthigi via Boost-users wrote: > I said that I am not sure if boost::variant supports __int128 because I > had difficulties in compiling this code : > > 1. > #include > 2. > #include <string> > 3. > #include <iostream> > 4. > std::ostream& operator<<(std::ostream& o, const __int128& x) { if (x > == std::numeric_limits<__int128>::min()) return o << > "-170141183460469231731687303715884105728"; if (x < 0) return o << > "-" << -x; if (x < 10) return o << (char)(x + '0'); return o << x / > 10 << (char)(x % 10 + '0'); } > 5. > int main() > 6. > { > 7. > boost::variant<__int128, char, std::string> v; > 8. > v = 56; > 9. > v = 'Y'; > 10. > __int128 d=12; > 11. > std::cout < 12. > std::cout << v << '\n'; > 13. > v = "Yashaswi raj"; > 14. > std::cout << v << '\n'; > 15. > } > > If u replace __int128 with int in the variant variable, it seems to work > just fine...

My test with gcc-10.2 and clang-linux-11.0 shows that it does not support __int128 in iostreams.

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Edward Diener

2:37 p.m.

On 4/7/2021 10:33 PM, Anil Muthigi via Boost-users wrote:

...

But I am not even doing any kind of input or output using __int128 FOR THE VARIANT VARIABLE….

As you can see… if you choose to use int instead of __int128 for the VARIANT VARIABLE and rerun the code…. it is actually printing the value of the __int128 variable d which I have used in the code.. So, I guess it is actually picking up my std::ostream& operator<<(std::ostream& o, const __int128& x) functionality.

I agree that variant does not support __int128. File a Issue report at https://github.com/boostorg/variant if you wish. I am not the variant maintainer. You may also try variant2.

...

...
On 08-Apr-2021, at 7:52 AM, Edward Diener via Boost-users mailto:boost-users@lists.boost.org> wrote:

On 4/7/2021 9:58 PM, Edward Diener via Boost-users wrote:

...
...
If u see my code, I have used __int128 separately for the variable d as well. If u change the variant variable' s data type from __int128 to int , it will run just fine. The reason your code is failing is because your stream operator uses streaming and __int128 has no stream support. If you use an __int128 in a variant, but never use streaming, your code is fine. I do not know the reason why gcc and clang support __int128 but do not support

On 4/7/2021 7:10 PM, Anil Muthigi via Boost-users wrote: the the type in streaming. Maybe you should try asking gcc about it or investigate it as a stackoverflow question. Please do not topmost.

Apologies ! It looks as if the variant i/o is simply not picking up your std::ostream& operator<<(std::ostream& o, const __int128& x) functionality. I tried putting your functionality in namespace boost but it still did not pick it up.

...
...
On Thu, 8 Apr 2021, 04:30 Edward Diener via Boost-users, mailto:boost-users@lists.boost.org mailto:boost-users@lists.boost.org>> wrote:

On 4/7/2021 3:38 PM, Anil Muthigi via Boost-users wrote:

...
I said that I am not sure if boost::variant supports __int128 because I had difficulties in compiling this code :

1. #include 2. #include <string> 3. #include <iostream> 4. std::ostream& operator<<(std::ostream& o, const __int128& x) { if (x == std::numeric_limits<__int128>::min()) return o << "-170141183460469231731687303715884105728"; if (x < 0) return o << "-" << -x; if (x < 10) return o << (char)(x + '0'); return o << x / 10 << (char)(x % 10 + '0'); } 5. int main() 6. { 7. boost::variant<__int128, char, std::string> v; 8. v = 56; 9. v = 'Y'; 10. __int128 d=12; 11. std::cout <
If u replace __int128 with int in the variant variable, it seems to work just fine...

My test with gcc-10.2 and clang-linux-11.0 shows that it does not support __int128 in iostreams.

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Anil Muthigi

2:43 a.m.

On running the code given below which uses int for variant variable but uses __int128 for the variable d having value 12... I get the following output = #include #include <string> #include <iostream> std::ostream& operator<<(std::ostream& o, const __int128& x) { if (x == std::numeric_limits<__int128>::min()) return o << "-170141183460469231731687303715884105728"; if (x < 0) return o << "-" << -x; if (x < 10) return o << (char)(x + '0'); return o << x / 10 << (char)(x % 10 + '0'); } int main() { boost::variant v; v = 56; v = 'Y'; __int128 d=12; std::cout <

...

On 08-Apr-2021, at 1:08 AM, Anil Muthigi wrote:

I said that I am not sure if boost::variant supports __int128 because I had difficulties in compiling this code : #include #include <string> #include <iostream> std::ostream& operator<<(std::ostream& o, const __int128& x) { if (x == std::numeric_limits<__int128>::min()) return o << "-170141183460469231731687303715884105728"; if (x < 0) return o << "-" << -x; if (x < 10) return o << (char)(x + '0'); return o << x / 10 << (char)(x % 10 + '0'); } int main() { boost::variant<__int128, char, std::string> v; v = 56; v = 'Y'; __int128 d=12; std::cout <
On Thu, 8 Apr 2021, 00:10 Edward Diener via Boost-users, mailto:boost-users@lists.boost.org> wrote: On 4/7/2021 2:15 PM, Anil Muthigi via Boost-users wrote:

...
I dont think so...

If it is available why do you think variant would not support it ?

...
I guess int128_t under boost/multiprecision/cpp_int is the only viable option.

On Wed, 7 Apr 2021, 11:39 pm David Frank via Boost-users, mailto:boost-users@lists.boost.org mailto:boost-users@lists.boost.org>> wrote:

especially the gnu __int128?

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Felipe Magno de Almeida

6:16 p.m.

Hello Anil, On Wed, Apr 7, 2021 at 11:43 PM Anil Muthigi via Boost-users < boost-users@lists.boost.org> wrote:

...

On running the code given below which uses int for variant variable but uses __int128 for the variable d having value 12... I get the following output =

You must define your operator<< in namespace std so it can be picked by ADL. Kind regards, PS: Do not use images to show code. Just write them in your email body. [snip - images] -- Felipe Magno de Almeida Owner @ Expertise Solutions www: https://expertise.dev phone: +55 48 9 9681.0157 LinkedIn: in/felipealmeida

Edward Diener

9:45 p.m.

On 4/8/2021 2:16 PM, Felipe Magno de Almeida via Boost-users wrote:

...

Hello Anil,

On Wed, Apr 7, 2021 at 11:43 PM Anil Muthigi via Boost-users mailto:boost-users@lists.boost.org> wrote:

On running the code given below which uses int for variant variable but uses __int128 for the variable d having value 12... I get the following output =

You must define your operator<< in namespace std so it can be picked by ADL.

If you just have: #include #include <string> boost::variant<__int128, char, std::string> v; v = 56; This produces an error: ..\..\../boost/variant/variant.hpp:1578:38: error: call of overloaded 'initialize(void*, boost::move_detail::remove_reference::type)' is ambiguous

...

Kind regards,

PS: Do not use images to show code. Just write them in your email body. [snip - images]

-- Felipe Magno de Almeida Owner @ Expertise Solutions www: https://expertise.dev https://expertise.dev phone: +55 48 9 9681.0157 LinkedIn: in/felipealmeida

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Gavin Lambert

10:05 p.m.

On 9/04/2021 9:45 am, Edward Diener wrote:

...

If you just have:

#include #include <string>

boost::variant<__int128, char, std::string> v; v = 56;

This produces an error:

..\..\../boost/variant/variant.hpp:1578:38: error: call of overloaded 'initialize(void*, boost::move_detail::remove_reference::type)' is ambiguous

To resolve that, use static_cast<__int128>(56) instead, or assign an __int128 variable instead of an integer constant.

Rainer Deyke

9 Apr 9 Apr

5:14 a.m.

On 08.04.21 23:45, Edward Diener via Boost-users wrote:

...

If you just have:

#include #include <string>

boost::variant<__int128, char, std::string> v; v = 56;

This produces an error:

..\..\../boost/variant/variant.hpp:1578:38: error: call of overloaded 'initialize(void*, boost::move_detail::remove_reference::type)' is ambiguous

That's because it /is/ ambiguous. The compiler does not know if you want to set the variant to a '__int128' or to a 'char'. You get the same error message if you substitute 'long' for '__int128'. -- Rainer Deyke (rainerd@eldwood.com)

Edward Diener

12:58 p.m.

On 4/7/2021 3:38 PM, Anil Muthigi via Boost-users wrote:

...

I said that I am not sure if boost::variant supports __int128 because I had difficulties in compiling this code :

1. #include 2. #include <string> 3. #include <iostream> 4. std::ostream& operator<<(std::ostream& o, const __int128& x) { if (x == std::numeric_limits<__int128>::min()) return o << "-170141183460469231731687303715884105728"; if (x < 0) return o << "-" << -x; if (x < 10) return o << (char)(x + '0'); return o << x / 10 << (char)(x % 10 + '0'); } 5. int main() 6. { 7. boost::variant<__int128, char, std::string> v; 8. v = 56; 9. v = 'Y'; 10. __int128 d=12; 11. std::cout <
If u replace __int128 with int in the variant variable, it seems to work just fine...

As others have pointed out, the correct code is: #include #include <string> #include <iostream> namespace std { std::ostream& operator<<(std::ostream& o, const __int128& x) { if (x == std::numeric_limits<__int128>::min()) return o << "-170141183460469231731687303715884105728"; if (x < 0) return o << "-" << -x; if (x < 10) return o << (char)(x + '0'); return o << x / 10 << (char)(x % 10 + '0'); } } int main() { boost::variant<__int128, char, std::string> v; v = static_cast<__int128>(56); v = 'Y'; __int128 d=12; std::cout << d << '\n'; std::cout << v << '\n'; v = "Yashaswi raj"; std::cout << v << '\n'; return 0; } So __int128 does indeed work with variant, as I originally surmised.

...

On Thu, 8 Apr 2021, 00:10 Edward Diener via Boost-users, mailto:boost-users@lists.boost.org> wrote:

On 4/7/2021 2:15 PM, Anil Muthigi via Boost-users wrote: > I dont think so...

If it is available why do you think variant would not support it ?

> I guess int128_t under boost/multiprecision/cpp_int is the only viable > option. > > On Wed, 7 Apr 2021, 11:39 pm David Frank via Boost-users, > mailto:boost-users@lists.boost.org mailto:boost-users@lists.boost.org>> wrote: > > especially the gnu __int128?

Edward Diener

7 Apr 7 Apr

6:35 p.m.

On 4/7/2021 2:00 PM, David Frank via Boost-users wrote:

...

especially the gnu __int128?

There is no reason why it would not support __int128 if it is available.

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Anil Muthigi
David Frank
Edward Diener
Felipe Magno de Almeida
Gavin Lambert
Rainer Deyke