I dont think so... I guess int128_t under boost/multiprecision/cpp_int is the only viable option. On Wed, 7 Apr 2021, 11:39 pm David Frank via Boost-users, < boost-users@lists.boost.org> wrote:
especially the gnu __int128? Thanks, David. _______________________________________________ Boost-users mailing list Boost-users@lists.boost.org https://lists.boost.org/mailman/listinfo.cgi/boost-users
On 4/7/2021 2:15 PM, Anil Muthigi via Boost-users wrote:
I dont think so...
If it is available why do you think variant would not support it ?
I guess int128_t under boost/multiprecision/cpp_int is the only viable option.
On Wed, 7 Apr 2021, 11:39 pm David Frank via Boost-users, <boost-users@lists.boost.org <mailto:boost-users@lists.boost.org>> wrote:
especially the gnu __int128?
I said that I am not sure if boost::variant supports __int128 because I had difficulties in compiling this code : 1. #include <boost/variant.hpp> 2. #include <string> 3. #include <iostream> 4. std::ostream& operator<<(std::ostream& o, const __int128& x) { if (x == std::numeric_limits<__int128>::min()) return o << "-170141183460469231731687303715884105728"; if (x < 0) return o << "-" << -x; if (x < 10) return o << (char)(x + '0'); return o << x / 10 << (char) (x % 10 + '0'); } 5. int main() 6. { 7. boost::variant<__int128, char, std::string> v; 8. v = 56; 9. v = 'Y'; 10. __int128 d=12; 11. std::cout <<d << '\n'; 12. std::cout << v << '\n'; 13. v = "Yashaswi raj"; 14. std::cout << v << '\n'; 15. } If u replace __int128 with int in the variant variable, it seems to work just fine... On Thu, 8 Apr 2021, 00:10 Edward Diener via Boost-users, < boost-users@lists.boost.org> wrote:
On 4/7/2021 2:15 PM, Anil Muthigi via Boost-users wrote:
I dont think so...
If it is available why do you think variant would not support it ?
I guess int128_t under boost/multiprecision/cpp_int is the only viable option.
On Wed, 7 Apr 2021, 11:39 pm David Frank via Boost-users, <boost-users@lists.boost.org <mailto:boost-users@lists.boost.org>> wrote:
especially the gnu __int128?
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On 4/7/2021 3:38 PM, Anil Muthigi via Boost-users wrote:
I said that I am not sure if boost::variant supports __int128 because I had difficulties in compiling this code :
1. #include <boost/variant.hpp> 2. #include <string> 3. #include <iostream> 4. std::ostream& operator<<(std::ostream& o, const __int128& x) { if (x == std::numeric_limits<__int128>::min()) return o << "-170141183460469231731687303715884105728"; if (x < 0) return o << "-" << -x; if (x < 10) return o << (char)(x + '0'); return o << x / 10 << (char)(x % 10 + '0'); } 5. int main() 6. { 7. boost::variant<__int128, char, std::string> v; 8. v = 56; 9. v = 'Y'; 10. __int128 d=12; 11. std::cout <<d << '\n'; 12. std::cout << v << '\n'; 13. v = "Yashaswi raj"; 14. std::cout << v << '\n'; 15. }
If u replace __int128 with int in the variant variable, it seems to work just fine...
My test with gcc-10.2 and clang-linux-11.0 shows that it does not support __int128 in iostreams.
On Thu, 8 Apr 2021, 00:10 Edward Diener via Boost-users, <boost-users@lists.boost.org <mailto:boost-users@lists.boost.org>> wrote:
On 4/7/2021 2:15 PM, Anil Muthigi via Boost-users wrote: > I dont think so...
If it is available why do you think variant would not support it ?
> I guess int128_t under boost/multiprecision/cpp_int is the only viable > option. > > On Wed, 7 Apr 2021, 11:39 pm David Frank via Boost-users, > <boost-users@lists.boost.org <mailto:boost-users@lists.boost.org> <mailto:boost-users@lists.boost.org <mailto:boost-users@lists.boost.org>>> wrote: > > especially the gnu __int128?
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If u see my code, I have used __int128 separately for the variable d as well. If u change the variant variable' s data type from __int128 to int , it will run just fine. On Thu, 8 Apr 2021, 04:30 Edward Diener via Boost-users, < boost-users@lists.boost.org> wrote:
On 4/7/2021 3:38 PM, Anil Muthigi via Boost-users wrote:
I said that I am not sure if boost::variant supports __int128 because I had difficulties in compiling this code :
1. #include <boost/variant.hpp> 2. #include <string> 3. #include <iostream> 4. std::ostream& operator<<(std::ostream& o, const __int128& x) { if (x == std::numeric_limits<__int128>::min()) return o << "-170141183460469231731687303715884105728"; if (x < 0) return o << "-" << -x; if (x < 10) return o << (char)(x + '0'); return o << x / 10 << (char)(x % 10 + '0'); } 5. int main() 6. { 7. boost::variant<__int128, char, std::string> v; 8. v = 56; 9. v = 'Y'; 10. __int128 d=12; 11. std::cout <<d << '\n'; 12. std::cout << v << '\n'; 13. v = "Yashaswi raj"; 14. std::cout << v << '\n'; 15. }
If u replace __int128 with int in the variant variable, it seems to work just fine...
My test with gcc-10.2 and clang-linux-11.0 shows that it does not support __int128 in iostreams.
On Thu, 8 Apr 2021, 00:10 Edward Diener via Boost-users, <boost-users@lists.boost.org <mailto:boost-users@lists.boost.org>>
wrote:
On 4/7/2021 2:15 PM, Anil Muthigi via Boost-users wrote: > I dont think so...
If it is available why do you think variant would not support it ?
> I guess int128_t under boost/multiprecision/cpp_int is the only viable > option. > > On Wed, 7 Apr 2021, 11:39 pm David Frank via Boost-users, > <boost-users@lists.boost.org <mailto:boost-users@lists.boost.org> <mailto:boost-users@lists.boost.org <mailto:boost-users@lists.boost.org>>> wrote: > > especially the gnu __int128?
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On 4/7/2021 7:10 PM, Anil Muthigi via Boost-users wrote:
If u see my code, I have used __int128 separately for the variable d as well. If u change the variant variable' s data type from __int128 to int , it will run just fine.
The reason your code is failing is because your stream operator uses streaming and __int128 has no stream support. If you use an __int128 in a variant, but never use streaming, your code is fine. I do not know the reason why gcc and clang support __int128 but do not support the the type in streaming. Maybe you should try asking gcc about it or investigate it as a stackoverflow question. Please do not topmost.
On Thu, 8 Apr 2021, 04:30 Edward Diener via Boost-users, <boost-users@lists.boost.org <mailto:boost-users@lists.boost.org>> wrote:
On 4/7/2021 3:38 PM, Anil Muthigi via Boost-users wrote: > I said that I am not sure if boost::variant supports __int128 because I > had difficulties in compiling this code : > > 1. > #include <boost/variant.hpp> > 2. > #include <string> > 3. > #include <iostream> > 4. > std::ostream& operator<<(std::ostream& o, const __int128& x) { if (x > == std::numeric_limits<__int128>::min()) return o << > "-170141183460469231731687303715884105728"; if (x < 0) return o << > "-" << -x; if (x < 10) return o << (char)(x + '0'); return o << x / > 10 << (char)(x % 10 + '0'); } > 5. > int main() > 6. > { > 7. > boost::variant<__int128, char, std::string> v; > 8. > v = 56; > 9. > v = 'Y'; > 10. > __int128 d=12; > 11. > std::cout <<d << '\n'; > 12. > std::cout << v << '\n'; > 13. > v = "Yashaswi raj"; > 14. > std::cout << v << '\n'; > 15. > } > > If u replace __int128 with int in the variant variable, it seems to work > just fine...
My test with gcc-10.2 and clang-linux-11.0 shows that it does not support __int128 in iostreams.
On 4/7/2021 9:58 PM, Edward Diener via Boost-users wrote:
On 4/7/2021 7:10 PM, Anil Muthigi via Boost-users wrote:
If u see my code, I have used __int128 separately for the variable d as well. If u change the variant variable' s data type from __int128 to int , it will run just fine.
The reason your code is failing is because your stream operator uses streaming and __int128 has no stream support. If you use an __int128 in a variant, but never use streaming, your code is fine. I do not know the reason why gcc and clang support __int128 but do not support the the type in streaming. Maybe you should try asking gcc about it or investigate it as a stackoverflow question.
Please do not topmost.
Apologies ! It looks as if the variant i/o is simply not picking up your std::ostream& operator<<(std::ostream& o, const __int128& x) functionality. I tried putting your functionality in namespace boost but it still did not pick it up.
On Thu, 8 Apr 2021, 04:30 Edward Diener via Boost-users, <boost-users@lists.boost.org <mailto:boost-users@lists.boost.org>> wrote:
On 4/7/2021 3:38 PM, Anil Muthigi via Boost-users wrote: > I said that I am not sure if boost::variant supports __int128 because I > had difficulties in compiling this code : > > 1. > #include <boost/variant.hpp> > 2. > #include <string> > 3. > #include <iostream> > 4. > std::ostream& operator<<(std::ostream& o, const __int128& x) { if (x > == std::numeric_limits<__int128>::min()) return o << > "-170141183460469231731687303715884105728"; if (x < 0) return o << > "-" << -x; if (x < 10) return o << (char)(x + '0'); return o << x / > 10 << (char)(x % 10 + '0'); } > 5. > int main() > 6. > { > 7. > boost::variant<__int128, char, std::string> v; > 8. > v = 56; > 9. > v = 'Y'; > 10. > __int128 d=12; > 11. > std::cout <<d << '\n'; > 12. > std::cout << v << '\n'; > 13. > v = "Yashaswi raj"; > 14. > std::cout << v << '\n'; > 15. > } > > If u replace __int128 with int in the variant variable, it seems to work > just fine...
My test with gcc-10.2 and clang-linux-11.0 shows that it does not support __int128 in iostreams.
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But I am not even doing any kind of input or output using __int128 FOR THE VARIANT VARIABLE…. As you can see… if you choose to use int instead of __int128 for the VARIANT VARIABLE and rerun the code…. it is actually printing the value of the __int128 variable d which I have used in the code.. So, I guess it is actually picking up my std::ostream& operator<<(std::ostream& o, const __int128& x) functionality.
On 08-Apr-2021, at 7:52 AM, Edward Diener via Boost-users <boost-users@lists.boost.org> wrote:
On 4/7/2021 9:58 PM, Edward Diener via Boost-users wrote:
On 4/7/2021 7:10 PM, Anil Muthigi via Boost-users wrote:
If u see my code, I have used __int128 separately for the variable d as well. If u change the variant variable' s data type from __int128 to int , it will run just fine. The reason your code is failing is because your stream operator uses streaming and __int128 has no stream support. If you use an __int128 in a variant, but never use streaming, your code is fine. I do not know the reason why gcc and clang support __int128 but do not support the the type in streaming. Maybe you should try asking gcc about it or investigate it as a stackoverflow question. Please do not topmost.
Apologies ! It looks as if the variant i/o is simply not picking up your std::ostream& operator<<(std::ostream& o, const __int128& x) functionality. I tried putting your functionality in namespace boost but it still did not pick it up.
On Thu, 8 Apr 2021, 04:30 Edward Diener via Boost-users, <boost-users@lists.boost.org <mailto:boost-users@lists.boost.org>> wrote:
On 4/7/2021 3:38 PM, Anil Muthigi via Boost-users wrote: > I said that I am not sure if boost::variant supports __int128 because I > had difficulties in compiling this code : > > 1. > #include <boost/variant.hpp> > 2. > #include <string> > 3. > #include <iostream> > 4. > std::ostream& operator<<(std::ostream& o, const __int128& x) { if (x > == std::numeric_limits<__int128>::min()) return o << > "-170141183460469231731687303715884105728"; if (x < 0) return o << > "-" << -x; if (x < 10) return o << (char)(x + '0'); return o << x / > 10 << (char)(x % 10 + '0'); } > 5. > int main() > 6. > { > 7. > boost::variant<__int128, char, std::string> v; > 8. > v = 56; > 9. > v = 'Y'; > 10. > __int128 d=12; > 11. > std::cout <<d << '\n'; > 12. > std::cout << v << '\n'; > 13. > v = "Yashaswi raj"; > 14. > std::cout << v << '\n'; > 15. > } > > If u replace __int128 with int in the variant variable, it seems to work > just fine...
My test with gcc-10.2 and clang-linux-11.0 shows that it does not support __int128 in iostreams.
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On 4/7/2021 10:33 PM, Anil Muthigi via Boost-users wrote:
But I am not even doing any kind of input or output using __int128 FOR THE VARIANT VARIABLE….
As you can see… if you choose to use int instead of __int128 for the VARIANT VARIABLE and rerun the code…. it is actually printing the value of the __int128 variable d which I have used in the code.. So, I guess it is actually picking up my std::ostream& operator<<(std::ostream& o, const __int128& x) functionality.
I agree that variant does not support __int128. File a Issue report at https://github.com/boostorg/variant if you wish. I am not the variant maintainer. You may also try variant2.
On 08-Apr-2021, at 7:52 AM, Edward Diener via Boost-users <boost-users@lists.boost.org <mailto:boost-users@lists.boost.org>> wrote:
On 4/7/2021 9:58 PM, Edward Diener via Boost-users wrote:
If u see my code, I have used __int128 separately for the variable d as well. If u change the variant variable' s data type from __int128 to int , it will run just fine. The reason your code is failing is because your stream operator uses streaming and __int128 has no stream support. If you use an __int128 in a variant, but never use streaming, your code is fine. I do not know the reason why gcc and clang support __int128 but do not support
On 4/7/2021 7:10 PM, Anil Muthigi via Boost-users wrote: the the type in streaming. Maybe you should try asking gcc about it or investigate it as a stackoverflow question. Please do not topmost.
Apologies ! It looks as if the variant i/o is simply not picking up your std::ostream& operator<<(std::ostream& o, const __int128& x) functionality. I tried putting your functionality in namespace boost but it still did not pick it up.
On Thu, 8 Apr 2021, 04:30 Edward Diener via Boost-users, <boost-users@lists.boost.org <mailto:boost-users@lists.boost.org> <mailto:boost-users@lists.boost.org <mailto:boost-users@lists.boost.org>>> wrote:
On 4/7/2021 3:38 PM, Anil Muthigi via Boost-users wrote:
I said that I am not sure if boost::variant supports __int128 because I had difficulties in compiling this code :
1. #include <boost/variant.hpp> 2. #include <string> 3. #include <iostream> 4. std::ostream& operator<<(std::ostream& o, const __int128& x) { if (x == std::numeric_limits<__int128>::min()) return o << "-170141183460469231731687303715884105728"; if (x < 0) return o << "-" << -x; if (x < 10) return o << (char)(x + '0'); return o << x / 10 << (char)(x % 10 + '0'); } 5. int main() 6. { 7. boost::variant<__int128, char, std::string> v; 8. v = 56; 9. v = 'Y'; 10. __int128 d=12; 11. std::cout <<d << '\n'; 12. std::cout << v << '\n'; 13. v = "Yashaswi raj"; 14. std::cout << v << '\n'; 15. }
If u replace __int128 with int in the variant variable, it seems to work just fine...
My test with gcc-10.2 and clang-linux-11.0 shows that it does not support __int128 in iostreams.
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On running the code given below which uses int for variant variable but uses __int128 for the variable d having value 12... I get the following output = #include <boost/variant.hpp> #include <string> #include <iostream> std::ostream& operator<<(std::ostream& o, const __int128& x) { if (x == std::numeric_limits<__int128>::min()) return o << "-170141183460469231731687303715884105728"; if (x < 0) return o << "-" << -x; if (x < 10) return o << (char)(x + '0'); return o << x / 10 << (char)(x % 10 + '0'); } int main() { boost::variant<int, char, std::string> v; v = 56; v = 'Y'; __int128 d=12; std::cout <<d << '\n'; std::cout << v << '\n'; v = "Yashaswi raj"; std::cout << v << '\n'; }
On 08-Apr-2021, at 1:08 AM, Anil Muthigi <anilmuthigi123@gmail.com> wrote:
I said that I am not sure if boost::variant supports __int128 because I had difficulties in compiling this code : #include <boost/variant.hpp> #include <string> #include <iostream> std::ostream& operator<<(std::ostream& o, const __int128& x) { if (x == std::numeric_limits<__int128>::min()) return o << "-170141183460469231731687303715884105728"; if (x < 0) return o << "-" << -x; if (x < 10) return o << (char)(x + '0'); return o << x / 10 << (char)(x % 10 + '0'); } int main() { boost::variant<__int128, char, std::string> v; v = 56; v = 'Y'; __int128 d=12; std::cout <<d << '\n'; std::cout << v << '\n'; v = "Yashaswi raj"; std::cout << v << '\n'; } If u replace __int128 with int in the variant variable, it seems to work just fine...
On Thu, 8 Apr 2021, 00:10 Edward Diener via Boost-users, <boost-users@lists.boost.org <mailto:boost-users@lists.boost.org>> wrote: On 4/7/2021 2:15 PM, Anil Muthigi via Boost-users wrote:
I dont think so...
If it is available why do you think variant would not support it ?
I guess int128_t under boost/multiprecision/cpp_int is the only viable option.
On Wed, 7 Apr 2021, 11:39 pm David Frank via Boost-users, <boost-users@lists.boost.org <mailto:boost-users@lists.boost.org> <mailto:boost-users@lists.boost.org <mailto:boost-users@lists.boost.org>>> wrote:
especially the gnu __int128?
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Hello Anil, On Wed, Apr 7, 2021 at 11:43 PM Anil Muthigi via Boost-users < boost-users@lists.boost.org> wrote:
On running the code given below which uses int for variant variable but uses __int128 for the variable d having value 12... I get the following output =
You must define your operator<< in namespace std so it can be picked by ADL. Kind regards, PS: Do not use images to show code. Just write them in your email body. [snip - images] -- Felipe Magno de Almeida Owner @ Expertise Solutions www: https://expertise.dev phone: +55 48 9 9681.0157 LinkedIn: in/felipealmeida
On 4/8/2021 2:16 PM, Felipe Magno de Almeida via Boost-users wrote:
Hello Anil,
On Wed, Apr 7, 2021 at 11:43 PM Anil Muthigi via Boost-users <boost-users@lists.boost.org <mailto:boost-users@lists.boost.org>> wrote:
On running the code given below which uses int for variant variable but uses __int128 for the variable d having value 12... I get the following output =
You must define your operator<< in namespace std so it can be picked by ADL.
If you just have: #include <boost/variant.hpp> #include <string> boost::variant<__int128, char, std::string> v; v = 56; This produces an error: ..\..\../boost/variant/variant.hpp:1578:38: error: call of overloaded 'initialize(void*, boost::move_detail::remove_reference<int&>::type)' is ambiguous
Kind regards,
PS: Do not use images to show code. Just write them in your email body. [snip - images]
-- Felipe Magno de Almeida Owner @ Expertise Solutions www: https://expertise.dev <https://expertise.dev> phone: +55 48 9 9681.0157 LinkedIn: in/felipealmeida
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On 9/04/2021 9:45 am, Edward Diener wrote:
If you just have:
#include <boost/variant.hpp> #include <string>
boost::variant<__int128, char, std::string> v; v = 56;
This produces an error:
..\..\../boost/variant/variant.hpp:1578:38: error: call of overloaded 'initialize(void*, boost::move_detail::remove_reference<int&>::type)' is ambiguous
To resolve that, use static_cast<__int128>(56) instead, or assign an __int128 variable instead of an integer constant.
On 08.04.21 23:45, Edward Diener via Boost-users wrote:
If you just have:
#include <boost/variant.hpp> #include <string>
boost::variant<__int128, char, std::string> v; v = 56;
This produces an error:
..\..\../boost/variant/variant.hpp:1578:38: error: call of overloaded 'initialize(void*, boost::move_detail::remove_reference<int&>::type)' is ambiguous
That's because it /is/ ambiguous. The compiler does not know if you want to set the variant to a '__int128' or to a 'char'. You get the same error message if you substitute 'long' for '__int128'. -- Rainer Deyke (rainerd@eldwood.com)
On 4/7/2021 3:38 PM, Anil Muthigi via Boost-users wrote:
I said that I am not sure if boost::variant supports __int128 because I had difficulties in compiling this code :
1. #include <boost/variant.hpp> 2. #include <string> 3. #include <iostream> 4. std::ostream& operator<<(std::ostream& o, const __int128& x) { if (x == std::numeric_limits<__int128>::min()) return o << "-170141183460469231731687303715884105728"; if (x < 0) return o << "-" << -x; if (x < 10) return o << (char)(x + '0'); return o << x / 10 << (char)(x % 10 + '0'); } 5. int main() 6. { 7. boost::variant<__int128, char, std::string> v; 8. v = 56; 9. v = 'Y'; 10. __int128 d=12; 11. std::cout <<d << '\n'; 12. std::cout << v << '\n'; 13. v = "Yashaswi raj"; 14. std::cout << v << '\n'; 15. }
If u replace __int128 with int in the variant variable, it seems to work just fine...
As others have pointed out, the correct code is: #include <boost/variant.hpp> #include <string> #include <iostream> namespace std { std::ostream& operator<<(std::ostream& o, const __int128& x) { if (x == std::numeric_limits<__int128>::min()) return o << "-170141183460469231731687303715884105728"; if (x < 0) return o << "-" << -x; if (x < 10) return o << (char)(x + '0'); return o << x / 10 << (char)(x % 10 + '0'); } } int main() { boost::variant<__int128, char, std::string> v; v = static_cast<__int128>(56); v = 'Y'; __int128 d=12; std::cout << d << '\n'; std::cout << v << '\n'; v = "Yashaswi raj"; std::cout << v << '\n'; return 0; } So __int128 does indeed work with variant, as I originally surmised.
On Thu, 8 Apr 2021, 00:10 Edward Diener via Boost-users, <boost-users@lists.boost.org <mailto:boost-users@lists.boost.org>> wrote:
On 4/7/2021 2:15 PM, Anil Muthigi via Boost-users wrote: > I dont think so...
If it is available why do you think variant would not support it ?
> I guess int128_t under boost/multiprecision/cpp_int is the only viable > option. > > On Wed, 7 Apr 2021, 11:39 pm David Frank via Boost-users, > <boost-users@lists.boost.org <mailto:boost-users@lists.boost.org> <mailto:boost-users@lists.boost.org <mailto:boost-users@lists.boost.org>>> wrote: > > especially the gnu __int128?
participants (6)
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Anil Muthigi -
David Frank -
Edward Diener -
Felipe Magno de Almeida -
Gavin Lambert -
Rainer Deyke