Re: [Boost-users] [Bind] Understanding protect

27 Mar 2012

      On Tue, Mar 27, 2012 at 7:25 PM, Gordon Woodhull wrote:
...
On Mar 27, 2012, at 2:13 PM, Robert Jones wrote:
...
Ultimately I'm doing this for each member of a
range, via std algorithm, so I need to bind a unary argument to produce
a nullary function
object, which I can then pass to an evaluation context, ie my g( )
function. If I've generated
the function object with bind and placeholder(s), it seems there's no
way to prevent the binding
of the last placeholder from triggering evaluation, when what I require
is an unevaluated nullary
function object.
Hmm, works for me, IIUC:
#include 
#include <iostream>
template<typename F>
void g(F const &f) {
 f();
}
void f(int x) {
 std::cout << "x is " << x << std::endl;
}
int main() {
 for(int i=0; i<7; ++i)
   g(boost::bind(f,i));
 return 0;
}
But how would that translate to this context...?

int main( )
{
    std::vector<int> v;
    v += 0,1,2,3,4,5,6;
    for_each( v.begin( ), v.end( ), /* ???? */ );
    return 0;
}

Thx, Rob.