On Tue, Mar 27, 2012 at 7:25 PM, Gordon Woodhull <gordon@woodhull.com> wrote:
On Mar 27, 2012, at 2:13 PM, Robert Jones wrote:
> Ultimately I'm doing this for each member of a
> range, via std algorithm, so I need to bind a unary argument to produce a nullary function
> object, which I can then pass to an evaluation context, ie my g( ) function. If I've generated
> the function object with bind and placeholder(s), it seems there's no way to prevent the binding
> of the last placeholder from triggering evaluation, when what I require is an unevaluated nullary
> function object.
Hmm, works for me, IIUC:
#include <boost/bind.hpp>
#include <iostream>
template<typename F>
void g(F const &f) {
f();
}
void f(int x) {
std::cout << "x is " << x << std::endl;
}
int main() {
for(int i=0; i<7; ++i)
g(boost::bind(f,i));
return 0;
But how would that translate to this context...?
int main( )
{
std::vector<int> v;
v += 0,1,2,3,4,5,6;
for_each( v.begin( ), v.end( ), /* ???? */ );
return 0;
}
Thx, Rob.