On running the code given below which uses int for variant variable but uses __int128 for the variable d having value 12... I get the following output =
#include
#include <string>
#include <iostream>
std::ostream& operator<<(std::ostream& o, const __int128& x) { if (x == std::numeric_limits<__int128>::min()) return o << "-170141183460469231731687303715884105728"; if (x < 0) return o << "-" << -x; if (x < 10) return o << (char)(x + '0'); return o << x / 10 << (char)(x % 10 + '0'); }
int main()
{
boost::variant v;
v = 56;
v = 'Y';
__int128 d=12;
std::cout <
On 08-Apr-2021, at 1:08 AM, Anil Muthigi wrote:
I said that I am not sure if boost::variant supports __int128 because I had difficulties in compiling this code :
#include
#include <string>
#include <iostream>
std::ostream& operator<<(std::ostream& o, const __int128& x) { if (x == std::numeric_limits<__int128>::min()) return o << "-170141183460469231731687303715884105728"; if (x < 0) return o << "-" << -x; if (x < 10) return o << (char)(x + '0'); return o << x / 10 << (char)(x % 10 + '0'); }
int main()
{
boost::variant<__int128, char, std::string> v;
v = 56;
v = 'Y';
__int128 d=12;
std::cout <
On Thu, 8 Apr 2021, 00:10 Edward Diener via Boost-users, mailto:boost-users@lists.boost.org> wrote:
On 4/7/2021 2:15 PM, Anil Muthigi via Boost-users wrote:
I dont think so...
If it is available why do you think variant would not support it ?
I guess int128_t under boost/multiprecision/cpp_int is the only viable
option.
On Wed, 7 Apr 2021, 11:39 pm David Frank via Boost-users,
mailto:boost-users@lists.boost.org mailto:boost-users@lists.boost.org>> wrote:
especially the gnu __int128?
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