actually i’m aware of this template. However, it does not take into account the involved binary operator. Am I missing something or is this template missing this customisation point? A related follow up question, looking at the vectors operator*, e.g., if i want to express the resulting type of a scalar multiplication with mixed types like a Vector of ints with a double scalar type. How can I implement that? The return type of that function overload is determined by deduce_vec<A>::type which only takes into account the vector data type and not the type for the scalar.

On 7. Dec 2020, at 21:29, Emil Dotchevski via Boost wrote:

See deduce_vec2 (https://boostorg.github.io/qvm/#deduce_vec2): this template is used by QVM whenever it needs to deduce a vector type of certain dimension from the types of two user-supplied function parameters (there is also deduce_vec, which is used by unary operations).

If you don't care about the resulting vector type but only about its scalar type, you can specialize deduce_scalar instead ( https://boostorg.github.io/qvm/#deduce_scalar), which is used by deduce_vec2 by default.

On Mon, Dec 7, 2020 at 8:58 AM Kai Szuttor via Boost wrote:

...

Hey all,

concerning vector operations in boost qvm, is it possible to somehow specify the return type of a binary operator with mixed scalar input data, e.g.

operator+(vec, vec)

?

Could not find the customisation point to do this depending on the involved operation.

Thanks in advance,

Kai

_______________________________________________ Unsubscribe & other changes: http://lists.boost.org/mailman/listinfo.cgi/boost

_______________________________________________ Unsubscribe & other changes: http://lists.boost.org/mailman/listinfo.cgi/boost