Hello, i was wondering if it makes sens to add the well known super or base keyword to the C++ language in a generic way. Here I have a simple example on how it would make inherited base or super class overloaded function calls easier. Example 1: class A { public: virtual void print() { std::cout << "A" << std::endl; } }; class B : public A { public: virtual void print() { std::cout << "B" << std::endl; std::cout << "super call "; A::print(); } }; class C : public B { public: virtual void print() { std::cout << "C" << std::endl; std::cout << "super call "; B::print(); } }; int main(int argc, char* argv[]) { A a; B b; C c; a.print(); // Prints A b.print(); // Prints B and super call A c.print(); // Prints C and super call B super call A return 0; } Adding a template class superable would avoid one to write the explicit base or super class name. Example 2: namespace boost { template<typename T> class superable : public T { public: typedef T super; // C++ and java style typedef T base; // C# style }; } class A { public: virtual void print() { std::cout << "A" << std::endl; } }; class B : boost::superable<A> { public: virtual void print() { std::cout << "B" << std::endl; std::cout << "super call "; super::print(); // C++ and java style call } }; class C : boost::superable<B> { public: virtual void print() { std::cout << "C" << std::endl; std::cout << "super call "; base::print(); // C# style call } }; int main(int argc, char* argv[]) { A a; B b; C c; a.print(); // Prints A b.print(); // Prints B and super call A c.print(); // Prints C and super call B super call A return 0; } If somebody could add this to the core boost library, that would be great. Sincerely yours, Max