----- "Robert Stewart" <Robert.Stewart@sig.com> a écrit :

Ivan Le Lann wrote:

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Le samedi 19 février 2011 à 19:37 +0100, Ion Gaztañaga a écrit :

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having to include a lot of std headers to declare a function with a std::string const reference as input parameter is a bit too much

For a function declaration, even when you pass/return by value, you only need to declare types.

That's true unless, as is the subject of this thread, the type you would like to forward declare is in namespace std. Then you get into the world of "as if." The implementer may declare std types with template parameters beyond those named in the standard, provided the extras are defaulted so the types work as if they didn't have the extra template parameters. If a type does have extra template parameters, however, forward declaring it without them means mismatching the declarations while including them means requires that they be defaulted correctly. Unfortunately, defaults can be specified only once.

Only std types that don't make use of defaulted template parameters could be forward declared and, even then, are nonportable, even among versions of the same standard library.

I think you missed my point. I was basically replying: s/const reference// to Ion, and no more than that. I did not intend to fix the std forwarding problem, as there is obviously no clean way to fix it, until <stdfwd> appears. Ivan