4 May
2010
4 May
'10
7:29 a.m.
on 03.05.2010 at 23:55 vicente.botet wrote :
In a post from yesterday it was said that the arithmetic operators were not implemented following move semantics. The signatures were given, but no replay to this post has been done yet. I'm sure that the poster was looking into the sources.
actually i don't see a reason to implement them that way rather they should be implemented either of two ways type operator@(type, const type&); type operator#(const type&, const type&); but not simultaneously in the first case move semantics will take place where appropriate -- Pavel P.S. if you notice a grammar mistake or weird phrasing in my message please point it out