Richard Hadsell wrote:
This is a bit off-topic, but you might consult Stroustrup. In his "The C++ Programming Language" (3rd or Special edition) he says in section 11.2, in reference to operator. and 2 others that can't be overloaded: "They take a name, rather than a value, as their second operand and provide the means of referring to members. Allowing them to be overloaded would lead to subtleties."
Easy fix: use functors. obj.func(); would actually do struct anonymous_1 { /* some compile-time reflection info here */ typedef boost::mpl::vector_c<char, 'f', 'u', 'n', 'c'> name; static const bool function = true; typedef boost::mpl::vector<> args; template<typename T> auto operator(T& t) -> decltype(t.func()) { return t.func() } }; obj.operator.(anonymous_1()); I think this would allow, for example, to directly call the member functions of the underlying object in boost.variant. Could someone confirm that?