[boost] [serialization] BOOST_CLASS_IMPLEMENTATION and partial template specalization

22 Oct 2004

      Hello,

Using BOOST_CLASS_IMPLEMENTATION there is no way to assign specific
serialization implementation to any specialization of some template class.
Suppose we have template class

    template <class Params>
    class LaserPointSerializationExpression
    {
     ...
    };
And we want that any specialization of this class should be
object_serializable. Simple use of

BOOST_CLASS_IMPLEMENTATION(LaserPointSerializationExpression,
boost::serialization::object_serializable);

will give us the following code
namespace boost { 
  namespace serialization { 
    template <> 
    struct implementation_level<LaserPointSerializationExpression > 
    { 
      typedef mpl::integral_c_tag tag; 
      typedef mpl::int_< boost::serialization::object_serializable > type; 
      static const int value = implementation_level::type::value; 
    }; 
  } 
}
which obviously will fail to compile. The correct code is
namespace boost { 
  namespace serialization { 
    template <class Params> 
    struct
implementation_level<asda::lpfio::LaserPointSerializationExpression<Params>
...
{ 
      typedef mpl::integral_c_tag tag; 
      typedef mpl::int_< boost::serialization::object_serializable > type; 
      static const int value = implementation_level::type::value; 
    }; 
  } 
}
But there's no macro such as BOOST_CLASS_IMPLEMENTATION to generate it. So I
think there should be special version of BOOST_CLASS_IMPLEMENTATION that
allows to generate implementation_level for any specialization of some
template.
-- 
______________________________
Vyacheslav E. Andrejev
System Architect, Excelsior, LLC
E-mail: vandrejev@excelsior-usa.com
ICQ: 7152604