3 May
2004
3 May
'04
4:02 p.m.
On Mon, May 03, 2004 at 09:42:16AM -0400, Arkadiy Vertleyb wrote:
Shortcut for:
BOOST_TYPEOF(_1 > 15 && _2 < 20) fun(_1 > 15 && _2 < 20);
On the other hand, since a lambda expression returns a default-constructed functor (does it? -- I am unable to verify it right now) the above doesn't make a lot of sence for Lambda... One can just write:
BOOST_TYPEOF(_1 > 15 && _2 < 20) fun;
I don't think so. I am pretty sure that _1 < 3.3 and _1 < 4.4 have the same _type_ (but they have different "double" _values_ encoded in the run-time structure when constructed). -- -Brian McNamara (lorgon@cc.gatech.edu)