Re: [boost] [type_erasure] Review started (July 18-27, 2012)

7 Aug 2012

      AMDG

On 08/07/2012 10:45 AM, Paul A. Bristow wrote:
...
This specialization of ostreamable:
template<>
struct ostreamable<class Os, const std::pair<const int, double>& >
{
    static void apply(Os& out, const std::pair<const int, double>& arg)
    {
      out << arg; // No operator<< of type 'Os'
   }
};
still doesn't resolve the requirement.
This is an explicit specialization which uses a
class called Os.  I think you intended a partial
specialization:

template<class Os>
struct ostreamable<Os, std::pair<const int, double> >;
...
type_erasure_print_map.cpp(140): error C2678: binary '<<' : no operator found which takes a
left-hand operand of type 'Os' (or there is no acceptable conversion)
In Christ,
Steven Watanabe