13 Apr
2011
13 Apr
'11
2:50 p.m.
On 13 April 2011 03:34, Anders Dalvander <boost@dalvander.com> wrote:
Or if std::less would be used instead of operator<.
While the undefined behavior goes away, all that std::less guarantees is a total ordering for pointers. It doesn't specify what that ordering actually is. -- Nevin ":-)" Liber <mailto:nevin@eviloverlord.com> (847) 691-1404