[boost] lexical_cast reviewed

16 Jul 2004

      after fidling around with template functions i discovered you could write lexical_cast without any template arguments _required_. Also I neat little C-Style cast although no one is probably interested in using that. Anyways the syntax is as followed for both:

// lexical cast improved:

string str = lexical_cast( 3.1415f );
int i = lexical_cast( "12345" );

// C-style cast fun!

string str = (cstyle_cast)3.1415f;
int i = (cstyle_cast)"12345";

I would say that anyone already using lexical_cast would'nt have a problem with the improved one. Let me know what you guys think and if we should implement that.

-Jason

SOURCE CODE:
#include <sstream>
using namespace std;

class cstyle_cast {
public:
 template <typename Source> cstyle_cast( const Source & source ) {
  ss << source;
 }

 template <typename Target> operator Target() {
  Target target;
  ss >> target;
  return target;
 }
private:
 stringstream ss;
};

class lexical_cast { 
public:
 template <typename Source> lexical_cast( const Source & source ) {
  ss << source;
 }

 template <typename Target> operator Target() {
  Target target;
  ss >> target;
  return target;
 }
private:
 stringstream ss;
};

int main()
{
  string str1 = (cstyle_cast)3.141592f;
  string str2 = lexical_cast(3.141592f);
}