Hi, Straight to the problem. Consider the situation, were a function accepts parameter pack and something need to be done with each argument (for example, we want to print each argument on a new line): template <typename... Args> void print(Args&&... a) { // print each a on a separate line } There's a known trick to do that: template <typename... Args> void print(Args&&... a) { (void) (int []){ 0, (std::cout << a << std::endl, 0)... }; } But the syntax is not very readable (and I always forget it and search for an example in Internet). I've tried to improve the syntax, and here's the result: template<typename... Args> void print(Args&&... a) { expand_if<Args...> { std::cout << a << '\n'... }; } Compete source could be found here: http://coliru.stacked-crooked.com/view?id=c2c59f22574671e5 Here's some more usage examples: template<typename... Args> void printer_int(Args&&... args) { expand { std::cout << std::abs(args) << std::endl..., std::cout << "Printing once again all the numbers: " << std::endl, std::cout << " Once again " << std::abs(args) << std::endl..., std::cout << "EOF Printing once again all the numbers." << std::endl }; } template<typename... Args> float sum(Args&&... args) { float res = 0; expand_if<Args...> { res += args... }; return res; } I hope this would be helpful for someone or it could be used as an argument for a proposal to extend C++ and allow simpler syntax: template<typename... Args> void print(Args&&... a) { std::cout << a << '\n'...; } P.S.: There was a nicer solution that newer required "_if<Args..>" : namespace detail { struct expand_impl final { template <class... Arg> constexpr inline expand_impl(Arg&&...) noexcept {} }; } template <class... Arg> using expand = detail::expand_impl; But unfortunately there's no way to force the compiler to evaluate expressions in constructor call from left to right. So it did not work on GCC (but work on Clang). -- Best regards, Antony Polukhin