On 8/25/04 11:05 AM, "Markus Schöpflin" <markus.schoepflin@comsoft.de> wrote:
Currently, the name mangling scheme used on this platform is the default one selected by the compiler. It turns out that this is a bad choice when compiling boost. The problem is illustrated by the following example:
---%<--- #include <iostream> using namespace std;
template <typename T> void foo(T const &x) { cout << "1" << endl; }
template <typename T> void foo(T * const &x) { cout << "2" << endl; }
int main() { foo("abc"); return 0; } --->%---
This prints out "2" with the default name mangling scheme. When manually selecting "ansi" as the name mangling scheme, the correct result "1" is printed.
Why is [1] the correct answer? The string has type "char const [4]". I thought that the array-to-pointer conversion will happen, turning the string to a "char const *", which will match [2] with "char" for "T". I'm guessing that you think the reference in [1] prevents the array-to-pointer conversion, so [1] is the better match with "char [4]" for "T". I am guessing your logic correctly? Does anyone know if [1] is supposed to be the right answer? (No need to petition to change to compiler settings to choose [1] if [2] is supposed to be the standard answer.) -- Daryle Walker Mac, Internet, and Video Game Junkie darylew AT hotmail DOT com