8 Oct
2012
8 Oct
'12
5:46 p.m.
On 7 October 2012 19:29, Evgeny Panasyuk <evgeny.panasyuk@gmail.com> wrote:
3. Hardness of checking leads to situation when some compilers may check more cases than others. Even newer versions of same compiler can be smarter than predecessor. Does that mean that code which was compiled OK on older version of compiler will be broken on new, "smarter" one?
I'd say yes. Is this really a different situation than a more aggressive optimizing compiler breaking old code that happened to be dependent on undefined behavior which just happened to work in the past? -- Nevin ":-)" Liber <mailto:nevin@eviloverlord.com> (847) 691-1404