On 07/18/12 01:29, Vicente J. Botet Escriba wrote:
Hi,,
In the example from the doc
http://steven_watanabe.users.sourceforge.net/type_erasure/libs/type_erasure/...
typedef mpl::vector< copy_constructible<_a>, copy_constructible<_b>, copy_constructible<_c>, constructible<_a(const _b&, const _c&)> > construct;
std::vector<double> vec; int i = 10; double d = 2.5; tuple<construct, _a&, _b, _c> t(vec, i, d); any<construct, _a> v(get<1>(t), get<2>(t));
I don't see which type is constructed and stored in v and how this type is given. That is I don't see how _a is binded. Could you help me?
I'd guess that a std::vector<double>&, more specifically the vec is stored as the _a& in the tuple<construct, _&a, _b, _c>. Hmm... Now I'm not sure anymore. Maybe it's a new std::vector<double> that's stored and the std::vector<double> CTOR args are 10 and double. IOW the equivalent of: std::vector<double> v_a(10,2.5) is stored in v? Could the documentation on this be clarified a bit? TIA. -regards, Larry