[boost] conversion operator to boost function

"Jeffrey Williams" wrote:

Hi all,

The following code compiles on mingw (gcc 3.4.5) but not on VC++ 8.0 express, and I am asking if anyone could tell me which compiler is right.

Here is simple test case:

struct caster { template<class T> operator boost::function<T>() const; };

void func(boost::function<void(int)>) { }

void foo() { func(caster()); }

This compiles on mingw (it doesn't link obviously) but it won't even compile on VC++ 8.0 express. I am assuming one or the other is incorrect (perhaps they both are) so which is it? and also, is there a proper way to do that conversion that would work on both compilers. doing a specific conversion operator boost::function<void(int)> does work on both, but not the template.

Jeff

This doesn't compile because function also defines an implicit conversion. template<class F> function(const F&); The call is ambiguous. The conversion to boost::function<void(int)> works because it is more specialized. I can't think of a way to do this offhand. In Christ, Steven Watanabe