Hello all, Is there a way to access the outer class `this` from a local class but without using inheritance? Let me explain with an example: class x { // outer class public: void g() {} void f() { this->g(); // (1) struct y: x { // local class *** using inheritance *** y(x* super): x(*super) {} // (2) void h() { this->g(); // (3) } }; y(this).h(); } }; *** Is there a way to do this but without inheriting `y` from `x`? *** At line (3), the local class `y` can access the outer class `x::g()` simply using `this` because `y` inherits from `x`. However, this inheritance requires to construct another object `x` when `y` is constructed as in line (2) adding runtime overhead and requiring `x` to have an accessible copy constructor. In my application, I need line (3) to essentially look like line (1) so you can program code inside `y` members as if it were inside `x` members. A part from that, the local class `y` could look as it is needed to solve this problem -- with some member variables, other member functions, etc. (For example, I tried to redefine `y::operator->()`/`y::operator*()` to return a pointer/reference to `x` but this does not work because `this->`/`*this` always retain its pointer semantics and they do not use the user defined operators...) Thank you very much. -- Lorenzo