On 07/01/2005 06:47 AM, Thorsten Ottosen wrote:
Larry Evans <cppljevans <at> cox-internet.com> writes: [snip]
Are there any plans to request a formal review so that it's eventually in boost? I tried boost/range; however, as indicated by comments in the above code, I had no luck.
Could you make an small example that shows what you want to do and why boost.range cannot do it?
What I want is: <-------- cut here -------- #include <utility> using namespace std; template<class StlContainer> struct const_iter_range : private std::pair < typename StlContainer::const_iterator , typename StlContainer::const_iterator > { typedef typename StlContainer::const_iterator iter_type ; typedef typename StlContainer::const_reference const_reference ; typedef std::pair<iter_type,iter_type> super_type ; const_iter_range(StlContainer const& a_container) : super_type(a_container.begin(), a_container.end()) {} const_reference operator*(void)const { return *(this->first); } void operator++(void) { ++(this->first); } bool empty(void)const { return (this->first) == (this->second); } };
-------- cut here -------- However, when I tested boost/range by copying and then simplifying libs/range/test/iterator_range.hpp, the closest I got was: <-------- cut here --------
typedef string::iterator iterator; typedef iterator_range<iterator> irange; string str = "hello world"; irange ir = make_iterator_range( str ); cout <<"print str:\n"; cout <<str<<"\n"; cout <<"iterating thru ri:\n"; range_iterator<string>::type ri(begin(ir)); for ( int i=0 ; i<2 //&& !(ri.empty()) ; ++i,++ri ) { cout <<*ri << "\n"; } return 0; }-------- cut here -------- Why doesn't range_iterator<X> have an empty method? It also seems a lot of trouble to first declare and initialize the iterator_range used as argument to range_iterator. What's the reason for not doing this directly from the iterator_range CTOR arg which could just be an stl container? I suspect I missed something, but it's not obvious, at least to me :(