5 May
2010
5 May
'10
5:37 p.m.
on 05.05.2010 at 4:22 Chad Nelson wrote :
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On 05/04/2010 02:44 PM, Stewart, Robert wrote:
Um, because that operator is used for i + j and returns the sum, right? Did I miss something?
I suspect you (Robert) might be looking at the unary + operator...
Doh! So I was. I didn't even look at the argument list when I saw it because I've never overloaded the unary +!
I don't know anyone who does, but I assume that someone out there, someone will, and would be irritated if it didn't work the same as the built in integer types.
that person is me definitly -- Pavel P.S. if you notice a grammar mistake or weird phrasing in my message please point it out