Re: [boost] [type_traits]type_traits for types with operator().

This looks cool. However what does it detect? Any operator() or nullary operator()?

It detects any operator(), because expression &detail::is_functional_composed<T>::operator() is ambiguos when detail::is_functional_composed<T> has two or more operator(). But is_callable looks really better. Sorry for suggestion. Best regards, Anton.