"Jody Hagins" <jody-boost-011304@atdesk.com> wrote in message news:20050323104956.15cd7630.jody-boost-011304@atdesk.com...
On Wed, 23 Mar 2005 09:01:51 -0600 "Michael Goldshteyn" <mgoldshteyn@earthlink.net> wrote:
There is a bug in the sample code which cause me a lot of grief in understanding how boost::any functions, this morning. At:
http://www.boost.org/doc/html/any/s02.html
The code: --- bool is_string(const boost::any & operand) { return any_cast<std::string>(&operand); }
should read:
bool is_string(const boost::any & operand) { return any_cast<std::string *>(&operand); } ---
Notice the addition of the asterisk.
The original example looks fine to me. Why do you think it is incorrect?
The original example casts from an any pointer to an std::string, using any_cast, and returns the result implicitly cast to a boolean. So: 1. What does it mean to cast from an any pointer to an std::string, using any_cast? 2. What does it mean to implicitly convert a string, the value returned from any_cast<string> to a boolean?