Hi! In a previous message I asked if lexical_cast could throw boost::numeric::positive_overflow when the parsing is ok but the value too large for the target type. this turned out to be difficult because it breaks existing code, alternatively there could be another exception derived from bad_lexical_cast that indicates the overflow but this seems to be a lot of work. another question is why does lexical_cast treat int8_t and uint8_t like char? technically I see no reason for this as c++ has three types: char, signed char and unsigned char. in my code I use only char for characters and signed/unsigned char as numbers. I know that the standard stream operator << treats signed/unsigned char as char but I know no explanation for this (I consider it a bug ;-) -Jochen