Re: [boost] hash_value( complex<T> )

Howard Hinnant wrote:

Given two values x and y, if x == y, it is convenient for hash(x) == hash(y).

In this situation, given a floating point value r, complex{r) == r, so it makes sense that hash(complex{r}) == hash(r). This might enable heterogeneous hash table lookup.

But that already doesn't hold in general for int/long, float/double, int/double, and so on.