j
k
j a
j l
Max Khesin wrote: [snip]
and by extension bind(f, _1, _2, _0)(x, y, z) would be equivalent to f(x, y)
I don't get it, what is _0 here? AFAICT bind(f, _1, _2)(x, y, z) is already the equivalent of f(x, y) -- Daniel Wallin
Back to the thread
Back to the list
