Janek Kozicki said: (by the date of Fri, 13 Oct 2006 07:42:25 +0200) ok. maybe you will like this: 75 failures in 13 libraries (37 are from non-broken platforms) non-broken broken total filesystem 0 2 2 io 1 iostreams 7 1 8 mpl 5 1 6 parameter 2 4 6 program_options 0 9 9 python 8 1 9 random 1 rational 3 2 5 serialization 4 14 18 spirit 4 3 7 test 1 1 2 utility 1 To get this: utility 1 0 1 simply comment the line marked with [1] The code for that: message += (str(self.numFailures()) + ' failures in ' + str(len(self.libraries)) + ' libraries') if any_broken_platforms: message += ' (' + str(self.numReportableFailures()) + ' are from non-broken platforms)' message += '\n\n non-broken broken total\n' # Display the number of failures per library for k in sorted_keys( self.libraries ): library = self.libraries[k] num_failures = library.numFailures() message += (' ' + library.name.ljust(22) + ' ' + str(library.numReportableFailures()).ljust(9) ) # [1] comment this "if" line if library.numReportableFailures() < num_failures: message += (' ' + str(num_failures - library.numReportableFailures() ).ljust(8) + ' ' + str(num_failures)) message += '\n' pass Anyway, I'm off with that. Take it or not :) -- Janek Kozicki |