As far as I know, no. If you find a true answer, please tell me. I had this problem once as well and looked into it on the newsgroups. There may be a non-portable way with the vtable and asm, but not generally. My suggestion would be to make a split _nv function that does the call struct B { virtual void f() { f_nv(); } void f_nv() {std::printf("B\n"); } }; struct D : B { virtual void f() { f_nv(); } void f_nv() { std::printf("D\n"); } }; And then bind _nv; Eric Niebler wrote:
Imagine I have a base class B with a virtual function f() that is overridden in a derived class D ...
struct B { virtual void f() { std::printf("B\n"); } }; struct D : B { virtual void f() { std::printf("D\n"); } };
Now, I can have a derived object D and call the base member directly using qualification:
D d; d.B::f(); // OK, called B::f
But if I take the address of B::f for use with boost::bind, I get a thunk that always uses virtual dispatch...
boost::bind( &B::f, _1 )( d ); // Hrm, calls D::f
What if I don't want the virtual dispatch, and I really want this to behave like d.B::f()?
I know this is not specifically a problem with boost::bind, but a more general property of (virtual) member function pointers. Is there any way to get a non-virtual member function pointer to a virtual member function? If there is a way, I'm sure I don't know it.