5 Aug
2008
5 Aug
'08
12:43 a.m.
On Mon, Aug 4, 2008 at 4:35 PM, Steven Watanabe <watanabesj@gmail.com> wrote:
It does call operator= when both operands have the same type. Thanks.
Is it then true that even foo::operator= throws, in the code below: variant<foo,int> a=foo(....); variant<foo,int> b=foo(....); a=b; we will never end up with an int in a? If that's the case, then maybe I missed something in the documentation. Emil Dotchevski Reverge Studios, Inc. http://www.revergestudios.com/reblog/index.php?n=ReCode