Douglas Gregor said: (by the date of Thu, 12 Oct 2006 12:00:48 -0400)
75 failures in 13 libraries filesystem (2) io (1) iostreams (8) mpl (6) parameter (6) program_options (9) python (9) random (1) rational (5) serialization (18) spirit (7) test (2) utility (1)
Hi Doug, after 10 minutes (no more), including some googling I produced this: 75 failures in 13 libraries (37 are from non-broken platforms) non-broken broken filesystem 0 2 io 1 iostreams 7 8 mpl 5 6 parameter 2 6 program_options 0 9 python 8 9 random 1 rational 3 5 serialization 4 18 spirit 4 7 test 1 2 utility 1 The key function here is string.ljust(). If you like this, here is the diff -u @@ -409,18 +409,17 @@ str(len(self.libraries)) + ' libraries') if any_broken_platforms: message += ' (' + str(self.numReportableFailures()) + ' are from non-broken platforms)' - message += '\n' + message += '\n\n non-broken broken\n' # Display the number of failures per library for k in sorted_keys( self.libraries ): library = self.libraries[k] num_failures = library.numFailures() - message += (' ' + library.name + ' (' + message += (' ' + library.name.ljust(22) + ' ' + str(library.numReportableFailures())) if library.numReportableFailures() < num_failures: - message += (' of ' + str(num_failures) - + ' failures are from non-broken platforms') - message += ')\n' + message += (' ' + str(num_failures)) + message += '\n' pass # If we have any broken platforms, tell the user how we're -- Janek Kozicki |