
20 Dec
2005
20 Dec
'05
11:52 p.m.
Gabriel Dos Reis wrote:
"Eric Niebler" <eric@boost-consulting.com> writes:
| Now look above it: "typedef foo const cfoo". So the type of the 3rd | operand is "rvalue of foo const". The 2nd operand gets converted to ^^^^^^^^^
[there is no type "rvalue of ..." as you said earlier]
Thanks for the correction. So, the above would be more properly stated, "the 3rd operand is an rvalue of type foo const," is that right? -- Eric Niebler Boost Consulting www.boost-consulting.com