7 May
2004
7 May
'04
7:59 a.m.
I agree. IMO the best answer for now is to generate the 2^N overloads of operator() for some user-selectable N. Unary and binary functions are so common that IMO usually N==2 will do it.
I second that. Maybe n==3 anyone? Best, John -- John Torjo Freelancer -- john@torjo.com -- http://www.torjo.com/logview/ - viewing/filtering logs is just too easy!