-----Original Message----- From: boost-bounces@lists.boost.org [mailto:boost-bounces@lists.boost.org] On Behalf Of John Maddock Sent: Monday, February 07, 2005 3:30 AM To: boost@lists.boost.org Subject: Re: [boost] find the subexpression that matched
is there an immediate way to access the sub-expression that matched instead of checking each "what" as in the following?
for (unsigned int i = 1; i < what.size(); ++i) { if (what[i].matched) {
Not currently, sorry, might be a useful addition though...
I'd like to tag a question onto the coattails of this one. I haven't given it much thought, so if there's a terribly obvious reason this wouldn't work from a theoretical standpoint (or it's already in the implementation), please let me down easy. <g> Okay, I know there's no reasonable way to parse arbitrarily-nested constructs with regexes, but it's always seemed to me that it might be almost as useful to be able to extract the number of times a captured submatch with one of the repetition operators following actually matched. I also can't think of a reason it couldn't be done, off the top of my head. Your take? That seemed to me related enough to the original question to justify appending it, rather than starting a new thread. Reid