Re: [boost] Any interest in bitstream class?

On 6/29/2013 12:40 PM, Mathias Gaunard wrote:

What should I do if I want to define the operators on my own user-defined type?

Write them. It should be easy. For example, this is all it takes for ibitstream to support std::bitset: template ibitstream &operator>>(ibitstream &ibs, std::bitset<N> &bs) { decltype(bs.to_ulong()) value; ibs.read(value, N); bs = static_cast<long>(value); return ibs; }

See Rob's response. I assumed ibitstream derived from istream. Is that not the case?

That is not the case. See my reply to Mathias' similar query at http://article.gmane.org/gmane.comp.lib.boost.devel/242607

Does the ibitstream even use similar virtual functions and buffering mechanisms as istream?

Well, it follows std::istringstream and therefore std::istream. As far as possible, ibitstream and bitbuf have the same member functions and semantics as std::istringstream and std::stringbuf.

I suspect writing the value directly to the stream (possibly after byte swapping) would be faster than shifts and bitwise ands and writing it byte per byte.

I agree. However, my main concern was stability through simplicity. There is plenty of room for optimization, which I plan to do. Paul