15 Jun
2012
15 Jun
'12
3:59 p.m.
on Fri Jun 15 2012, Mathias Gaunard <mathias.gaunard-AT-ens-lyon.org> wrote:
On 15/06/2012 06:42, Dave Abrahams wrote:
on Tue Jun 12 2012, Mathias Gaunard<mathias.gaunard-AT-ens-lyon.org> wrote:
It is not natural for something written as foo = bar(); to change foo if bar fails.
But you usually can't tell the difference between bar() failing and the assignment failing, and it's perfectly natural for a failed assignment to change the assignee.
I can tell perfectly fine with
T foo;
try { foo = bar(); } catch(...) { }
1. How can you tell whether bar failed or the assignment failed, here? 2. Do you really write code like that?
// what state is foo in now?
Exactly my question. -- Dave Abrahams BoostPro Computing http://www.boostpro.com