
Hello, I first posted this two weeks ago for the review, allow me to repost just in case it went unnoticed: ----- Original Message ----- From: "vicente.botet" <vicente.botet@wanadoo.fr> To: <boost@lists.boost.org> Sent: Saturday, January 24, 2009 12:38 AM Subject: Re: [boost] Futures Review - can move_dest_type be public?
Hi,
The function get is defined in the documentation with following prototypes
R&& unique_future::get(); R& unique_future<R&>::get(); void unique_future<void>::get();
But when the move semantic is emulated this is just translated as
move_dest_type get()
with move_dest_type defined depending on the future template parameter as follows
typedef typename detail::future_traits<R>::move_dest_type move_dest_type;
template<typename T> struct future_traits { #ifdef BOOST_HAS_RVALUE_REFS typedef T const& source_reference_type; struct dummy; typedef typename boost::mpl::if_<boost::is_fundamental<T>,dummy&,T&&>::type rvalue_source_type; typedef typename boost::mpl::if_<boost::is_fundamental<T>,T,T&&>::type move_dest_type; #else typedef T& source_reference_type; typedef typename boost::mpl::if_<boost::is_convertible<T&,boost::detail::thread_move_t<T> >,boost::detail::thread_move_t<T>,T const&>::type rvalue_source_type; typedef typename boost::mpl::if_<boost::is_convertible<T&,boost::detail::thread_move_t<T> >,boost::detail::thread_move_t<T>,T>::type move_dest_type; #endif
};
Generic libraries using the futures needs to get the type returned by get. What do you think about making the move_dest_type public at least when BOOST_HAS_RVALUE_REFS is not defined? Another option would be to make public the future_traits class.
Best, Vicente
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