Richard Hodges wrote:
Forgive me chiming in late, but what is the semantic difference between:
There are various ways to represent the same four-state variant syntactically, and the main difference is in, well, syntax, when referring to it. You could, for example, use
outcome
> (assuming a never-empty tri-state outcome)
or
outcome
std::path> Completely agree that in this case optionalstd::path is equivalent to variant
. My concern is around allowing more than two
On 2 June 2017 at 18:43, Peter Dimov via Boost
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