I have a question about the memory pool allocation that boost implements. Suppose we do the following: std::vector<int, boost::pool_allocator<int> > v; for (int i = 0; i < 10; ++i) v.push_back(-1); And the std::vector<int> is implemented so that it starts out with reserved space of 1 and doubles space every time. So At the end of the above loop v will have size 10 and reserved size 16. Does the boost allocator mean that there will memory arrays lieing around of size 1,2,4,8 that can be reused ? Eg if you do this: std::vector<int, boost::pool_allocator<int> > v; for (int i = 0; i < 10; ++i) v.push_back(-1); std::vector<int, boost::pool_allocator<int> > v2; for (int i = 0; i < 8; ++i) v2.push_back(-1); There will be no system call needed to get more memory - v2 will just reuse the memory in the pool_allocator<int> ? Thanks. Steve. --------------------------------- Take the Internet to Go: Yahoo!Go puts the Internet in your pocket: mail, news, photos & more.