Maciej Sobczak <prog@msobczak.com> writes:
Hi,
We (the shop where I try to promote Boost) are using Boost 1.30.2 and currently the main focus is on interpreter embedding with Boost.Python.
I've hit a hard problem with this library. For some reason, I would like to clean up the Python interpreter after performing some coputations with it and possibly reinitialize it later, if there is again a need to do some scripting.
In other words, my use of Python interpreter is tightly scoped and there are repetitive calls to Py_Initialize() and Py_Finalize() functions during the lifetime of the application.
The problem is that the initialization code that executes inside the BOOST_PYTHON_MODULE block (more specifically: the class_'s "definitions") throws when execituting for a second time:
"trying to register to_python_converter for a type which already has a registered to_python_converter"
Right; re-starting Boost.Python isn't yet supported. Also, Py_Finalize() isn't supported with Boost.Python at the moment. See http://www.boost.org/libs/python/todo.html#pyfinalize-safety....
This code is executed as a result of "from mymodule import *" Python command; the second execution is a result of running this command in the interpreter that was already finalized and RE-initialized.
Is there a way to re-initialize the module without re-registering the converters?
Hacking the Boost.Python library is a valid option, but I would need at least a suggestion where should I go.
You should start by going to the c++-sig: http://www.boost.org/more/mailing_lists.htm#cplussig ;-) We can discuss further possibilities there. -- Dave Abrahams Boost Consulting www.boost-consulting.com