Re: [boost] [BGL] Visual Studio 12 finish_edge() failure, general BOOST_TTI_HAS_MEMBER_FUNCTION failure?

On 3/31/2014 1:27 PM, Michael Behrns-Miller wrote:

Hello boost!

In the BGL, finish_edge() is a visitor function of DFS, but it is optional. It is made optional via BOOST_TTI_HAS_MEMBER_FUNCTION. Here's how BGL defines it:

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BOOST_TTI_HAS_MEMBER_FUNCTION(finish_edge)

template <bool IsCallable> struct do_call_finish_edge { template static void call_finish_edge(Vis& vis, const E& e, const G& g) { vis.finish_edge(e, g); } };

template <> struct do_call_finish_edge<false> { template static void call_finish_edge(Vis&, const E&, const G&) {} };

template void call_finish_edge(Vis& vis, const E& e, const G& g) { // Only call if method exists do_call_finish_edge::value>::call_finish_edge(vis, e, g); }

The invocation of has_member_function_finish_edge has to match the member function signature which you are invoking. If the member function signature for finish_edge is: void finish_edge(const E&, const G&); then your invocation for do_call_finish_edge must be: do_call_finish_edge < has_member_function_finish_edge < Vis, void, boost::mpl::vector < const E&, const G& > > ::value

::call_finish_edge(vis, e, g);

or do_call_finish_edge < has_member_function_finish_edge < void Vis::* (const E&,const G&) > ::value

::call_finish_edge(vis, e, g);