Le mer 21/07/2004 à 14:25, Synge Todo a écrit :
From: David Abrahams <dave@boost-consulting.com> Date: Wed, 21 Jul 2004 07:20:20 -0400
I am a bit confused. Can "using std::pow;" be accepted by the compilers without a declaration of std::pow?
No it can't.
Thank you, David. It means that we have to always include <cmath> beforehand whenever we include Boost.Random headers, since it contains a line declaring "using std:pow;". This applies even if we just include Boost.Random headers without any instantiation of Boost.Random class templates. Isn't this requirement too strong for users???
No, I would say it means Boost.Random should include <cmath>. It's what you were suggesting at first (I think it was you). It's also what the other Boost libraries do (at least the Interval library does it). Regards, Guillaume