Re: [boost] Re: [review results] hash functions accepted

Thorsten Ottosen wrote:

So I think that we are just getting a false sense of security out of leaving the default empty.

OK, let's leave equivalence out of it. What is the default for an arbitrary object x of user-defined type X? You claim that it's hash_range( x.begin(), x.end() ), but this is obviously incorrect in the vast majority of cases. I claim that there is no default.