Hi Eric, On 30 Jan 2007, at 18:47, Eric Niebler wrote:
Steven Watanabe wrote:
accum_set; accum_set(1.0); accum_set(2.0); accum_set.drop<tag::sum>(); accum_set(3.0); std::cout << mean(accum_set) << std::endl; //prints 1 } This behavior can easily cause surprises. It must be fixed to print 2. I'm not quite sure how to implement it correctly. I think that probably you need to store the result at the point that drop is called for external lookup and continue to collect data for internal usage. Of course,
int main() { accumulator_set<double, features<tag::mean, droppable<tag::sum> this only applies in the face of dependencies.
The code is doing something a little unusual, but the result looks correct to me. What do you think the result should be, and why?
It should be 2. Note that if mean depends on sum, you cannot drop the accumulation of sum. If I remember our design discussions correctly then the "drop" would only drop the feature if it is not required for another non-dropped feature. Matthias