27 Jun
2005
27 Jun
'05
8:11 p.m.
"Robert Ramey" <ramey@rrsd.com> writes:
1) as written above, it fails to compile on a conforming compler. This is because the << operator takes a reference as its argument.
Why is it a good idea for << to take its 2nd argument by non-const reference?? -- Dave Abrahams Boost Consulting www.boost-consulting.com