On Sat, Jan 8, 2011 at 9:19 AM, Hartmut Kaiser <hartmut.kaiser@gmail.com>wrote:
I might give that a shot as I can't seem to get local variables to solve my problem. I would expect these two commands to have the same result (albeit unnecessarily assigning the _a variable, which just gets tossed away anyway), but apparently they are not?
r = p[_a = _1] r = p
Automatic attribute propagation from the rhs expression to the lhs rule is disabled as soon as semantic actions are involved. If you want to enforce attribute propagation anyways, write:
rule<...> r; r %= p[...];
If the rhs has no semantic actions attached, operator=() behaves exactly like operator%=().
That does the trick. Apologies for the previous top-post. I've been out of the mailing list game for a while now =) This style ended up working and I can finally move on to other things: r %= p1[_a = _1] >> ('*' | (eps[bind(&class::undo, &instance, _a)] >> !eps))
p2