Re: [boost] [property] interest in C# like properties for C++?

21 Oct 2009

      Hi,
I've been thinking about adding properties to C++ for some time, and I've
written several different Property<T> classes, so I've been following this
discussion with great interest. IMO C# properties are not as useful as they
should be; I think that ideally a property is a declarative expression that
automatically generates getter and/or setter code. 

For example I've been experimenting with a syntax that looks like this:

struct Example
{
	explicit Example( std::string& strName):
		name( strName ),
		count( 0 )
	{
	}

	Property< std::string, public_get, private_set> name;
	Property< int, public_get, public_set>		count;
};

Now I should be able to write:

void SomeFunc( std::string& strValue )
{
	Example x( strValue );
	x.count = 5;

	int I = x.count;
	std::string strName = x.name;
}

The point to this exercise is that as a developer I want to write less code,
not more. Here I see an opportunity to build a system to generate code for
me. So rather than emulate C# properties, I'm hoping that C++ can come up
with something better.

David

-----Original Message-----
From: boost-bounces@lists.boost.org [mailto:boost-bounces@lists.boost.org]
On Behalf Of Stefan Strasser
Sent: Tuesday, October 20, 2009 1:30 PM
To: boost@lists.boost.org
Subject: Re: [boost] [property] interest in C# like properties for C++?

Am Tuesday 20 October 2009 22:07:28 schrieb Matthew Chambers:
...
Do you plan to have a macro for defining simple/trivial properties with
a single line?
I think that this is the only thing that's missing from c++, and that it 
doesn't need a C# properties syntax.

the C++ "properties" syntax is, for example (taken from tr1::unordered_map):

float max_load_factor() const;
void max_load_factor(float z);

I wouldn't even consider your proposed properties syntax "syntactic sugar". 
it's just a different syntax, not a better one imho.

so if there's anything missing from c++ it would be something like

#define BOOST_TRIVIAL_PROPERTY(T,name) \
  T name() const{ return _name; } \
  void name(T __name){ _name=__name; } \
  T _name;

some of the problems your syntax introduces have already been mentioned. 
another one is that the getters and setters can not be virtual. C# and 
C++/CLI allow overriding setters and getters, and pure virtual properties, 
but I don't think that can be achieved with the same syntax in C++, since 
setters/getters are functions of seperate nested classes.
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Re: [boost] [property] interest in C# like properties for C++?

David Brownstein