At Mon, 20 Dec 2010 00:21:26 +0100, Jochen Wilhelmy wrote:
Hi!
is there a (possibly boost powered) way of distinguishing between const char* and const char[N]?
e.g.
const char* foo = "foo"; bar(foo); bar("foo");
The second call to bar should extract the length at compile time, e.g.
template <size_t length> void bar(const char (&data)[length]) {...}
The problem is that in the presence of the first variant (void bar(const char*)) the second variant does not get called.
// untested! #include <boost/enable_if.hpp> #include <boost/type_traits/is_same.hpp> #include <boost/type_traits/remove_pointer.hpp> typedef whatever1 returntype1; typedef whatever2 returntype2; template <class T> typename boost::enable_if< boost::is_same< const typename boost::remove_pointer<T>::type , char const >, returntype1>::type int bar(T); template <unsigned N> returntype2 bar(char const(&)[N]); HTH, -- Dave Abrahams BoostPro Computing http://www.boostpro.com