Stjepan Rajko wrote:
I am wondering if there is a construct in boost which, given a type T, returns the underlying "storable" type - say if T is int & the "storable_type" should be int. I'm not sure if the word "storable" is the best word...
The scenario I am facing is making a function call that takes a parameter of type T, where I need to prepare the parameter before calling (specifically, deserializing it from an archive). Hence, as far as I can tell, I need to declare a variable of the underlying storable type, and get the right value inside it.
So far, I've been using:
template<typename T> struct storable : public boost::remove_const<typename boost::remove_reference<T>::type > {};
but I'm not sure if that cuts it in all situations. In any case, I figured the right thing might be in Boost already and I just haven't found it.
No we don't have that one, well there had to be one :-) Your code will only work for class types right? If that's an acceptable limitation then it will do what you want, or did you mean: template<typename T> struct storable { typedef typename boost::remove_const<typename boost::remove_reference<T>::type > type; }; ??? Which would work for just about everything except function types (may need to be degraded to pointer-to-function), and abstract types. HTH, John.