19 May
2005
19 May
'05
8:14 p.m.
In-Reply-To: <d6dhiu$hai$1@sea.gmane.org> technews@kangaroologic.com (Jonathan Turkanis) wrote (abridged):
Are we going to generalise it to allow any (compile-time constant) terminator?
Why does the terminator have to be a compile-time constant?
I was hesitant about suggesting a generalisation which added run-time overhead over only supporting '\0'. Also, the need is not very common in my experience. -- Dave Harris, Nottingham, UK.